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+/* strcasestr.c - Find if one string appears as a substring of another string,
+ without regard to case. */
+
+/* Copyright (C) 2000 Free Software Foundation, Inc.
+
+ This file is part of GNU Bash, the Bourne Again SHell.
+
+ Bash is free software: you can redistribute it and/or modify
+ it under the terms of the GNU General Public License as published by
+ the Free Software Foundation, either version 3 of the License, or
+ (at your option) any later version.
+
+ Bash is distributed in the hope that it will be useful,
+ but WITHOUT ANY WARRANTY; without even the implied warranty of
+ MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
+ GNU General Public License for more details.
+
+ You should have received a copy of the GNU General Public License
+ along with Bash. If not, see <http://www.gnu.org/licenses/>.
+*/
+
+#include <config.h>
+
+#include <bashansi.h>
+#include <chartypes.h>
+
+#include <stdc.h>
+
+/* Determine if s2 occurs in s1. If so, return a pointer to the
+ match in s1. The compare is case insensitive. This is a
+ case-insensitive strstr(3). */
+char *
+strcasestr (s1, s2)
+ const char *s1;
+ const char *s2;
+{
+ register int i, l, len, c;
+
+ c = TOLOWER ((unsigned char)s2[0]);
+ len = strlen (s1);
+ l = strlen (s2);
+ for (i = 0; (len - i) >= l; i++)
+ if ((TOLOWER ((unsigned char)s1[i]) == c) && (strncasecmp (s1 + i, s2, l) == 0))
+ return ((char *)s1 + i);
+ return ((char *)0);
+}