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Diffstat (limited to 'JavaScriptCore/tests/mozilla/ecma/Math/15.8.2.18.js')
| -rw-r--r-- | JavaScriptCore/tests/mozilla/ecma/Math/15.8.2.18.js | 98 |
1 files changed, 98 insertions, 0 deletions
diff --git a/JavaScriptCore/tests/mozilla/ecma/Math/15.8.2.18.js b/JavaScriptCore/tests/mozilla/ecma/Math/15.8.2.18.js new file mode 100644 index 0000000..f745dd7 --- /dev/null +++ b/JavaScriptCore/tests/mozilla/ecma/Math/15.8.2.18.js @@ -0,0 +1,98 @@ +/* The contents of this file are subject to the Netscape Public + * License Version 1.1 (the "License"); you may not use this file + * except in compliance with the License. You may obtain a copy of + * the License at http://www.mozilla.org/NPL/ + * + * Software distributed under the License is distributed on an "AS + * IS" basis, WITHOUT WARRANTY OF ANY KIND, either express or + * implied. See the License for the specific language governing + * rights and limitations under the License. + * + * The Original Code is Mozilla Communicator client code, released March + * 31, 1998. + * + * The Initial Developer of the Original Code is Netscape Communications + * Corporation. Portions created by Netscape are + * Copyright (C) 1998 Netscape Communications Corporation. All + * Rights Reserved. + * + * Contributor(s): + * + */ +/** + File Name: 15.8.2.18.js + ECMA Section: 15.8.2.18 tan( x ) + Description: return an approximation to the tan of the + argument. argument is expressed in radians + special cases: + - if x is NaN result is NaN + - if x is 0 result is 0 + - if x is -0 result is -0 + - if x is Infinity or -Infinity result is NaN + Author: christine@netscape.com + Date: 7 july 1997 +*/ + + var SECTION = "15.8.2.18"; + var VERSION = "ECMA_1"; + startTest(); + var TITLE = "Math.tan(x)"; + var EXCLUDE = "true"; + + writeHeaderToLog( SECTION + " "+ TITLE); + + var testcases = getTestCases(); + test(); + +function getTestCases() { + var array = new Array(); + var item = 0; + + array[item++] = new TestCase( SECTION, "Math.tan.length", 1, Math.tan.length ); + + array[item++] = new TestCase( SECTION, "Math.tan()", Number.NaN, Math.tan() ); + array[item++] = new TestCase( SECTION, "Math.tan(void 0)", Number.NaN, Math.tan(void 0)); + array[item++] = new TestCase( SECTION, "Math.tan(null)", 0, Math.tan(null) ); + array[item++] = new TestCase( SECTION, "Math.tan(false)", 0, Math.tan(false) ); + + array[item++] = new TestCase( SECTION, "Math.tan(NaN)", Number.NaN, Math.tan(Number.NaN) ); + array[item++] = new TestCase( SECTION, "Math.tan(0)", 0, Math.tan(0)); + array[item++] = new TestCase( SECTION, "Math.tan(-0)", -0, Math.tan(-0)); + array[item++] = new TestCase( SECTION, "Math.tan(Infinity)", Number.NaN, Math.tan(Number.POSITIVE_INFINITY)); + array[item++] = new TestCase( SECTION, "Math.tan(-Infinity)", Number.NaN, Math.tan(Number.NEGATIVE_INFINITY)); + array[item++] = new TestCase( SECTION, "Math.tan(Math.PI/4)", 1, Math.tan(Math.PI/4)); + array[item++] = new TestCase( SECTION, "Math.tan(3*Math.PI/4)", -1, Math.tan(3*Math.PI/4)); + array[item++] = new TestCase( SECTION, "Math.tan(Math.PI)", -0, Math.tan(Math.PI)); + array[item++] = new TestCase( SECTION, "Math.tan(5*Math.PI/4)", 1, Math.tan(5*Math.PI/4)); + array[item++] = new TestCase( SECTION, "Math.tan(7*Math.PI/4)", -1, Math.tan(7*Math.PI/4)); + array[item++] = new TestCase( SECTION, "Infinity/Math.tan(-0)", -Infinity, Infinity/Math.tan(-0) ); + +/* + Arctan (x) ~ PI/2 - 1/x for large x. For x = 1.6x10^16, 1/x is about the last binary digit of double precision PI/2. + That is to say, perturbing PI/2 by this much is about the smallest rounding error possible. + + This suggests that the answer Christine is getting and a real Infinity are "adjacent" results from the tangent function. I + suspect that tan (PI/2 + one ulp) is a negative result about the same size as tan (PI/2) and that this pair are the closest + results to infinity that the algorithm can deliver. + + In any case, my call is that the answer we're seeing is "right". I suggest the test pass on any result this size or larger. + = C = +*/ + array[item++] = new TestCase( SECTION, "Math.tan(3*Math.PI/2) >= 5443000000000000", true, Math.tan(3*Math.PI/2) >= 5443000000000000 ); + array[item++] = new TestCase( SECTION, "Math.tan(Math.PI/2) >= 5443000000000000", true, Math.tan(Math.PI/2) >= 5443000000000000 ); + + return ( array ); +} +function test() { + for ( tc=0; tc < testcases.length; tc++ ) { + testcases[tc].passed = writeTestCaseResult( + testcases[tc].expect, + testcases[tc].actual, + testcases[tc].description +" = "+ + testcases[tc].actual ); + + testcases[tc].reason += ( testcases[tc].passed ) ? "" : "wrong value "; + } + stopTest(); + return ( testcases ); +} |