Switch the SetVector::remove_if implementation to use partition which

preserves the values of the relocated entries, unlikely remove_if. This
allows walking them and erasing them.

Also flesh out the predicate we are using for this to support the
various constraints actually imposed on a UnaryPredicate -- without this
we can't compose it with std::not1.

Thanks to Sean Silva for the review here and noticing the issue with
std::remove_if.

git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@165073 91177308-0d34-0410-b5e6-96231b3b80d8

1 files changed, 3 insertions, 2 deletions

diff --git a/include/llvm/ADT/SetVector.h b/include/llvm/ADT/SetVector.h
index e8d63ed..0ff0f46 100644
--- a/include/llvm/ADT/SetVector.h
+++ b/include/llvm/ADT/SetVector.h
@@ -141,8 +141,9 @@ public:
   /// \returns true if any element is removed.
   template <typename UnaryPredicate>
   bool remove_if(UnaryPredicate P) {
-    typename vector_type::iterator B = std::remove_if(vector_.begin(),
-                                                      vector_.end(), P),
+    typename vector_type::iterator B = std::partition(vector_.begin(),
+                                                      vector_.end(),
+                                                      std::not1(P)),
                                    E = vector_.end();
     if (B == E)
       return false;