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author | Nick Lewycky <nicholas@mxc.ca> | 2009-01-02 18:54:17 +0000 |
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committer | Nick Lewycky <nicholas@mxc.ca> | 2009-01-02 18:54:17 +0000 |
commit | ae285bf5a631e7dd24cce087eca78353ff231a9c (patch) | |
tree | 074ea712ec738862611916f0994f712ef6b43273 /lib/Analysis | |
parent | 98117cdbd6f2e371a3d4905a2b5ce26b2fb41d2c (diff) | |
download | external_llvm-ae285bf5a631e7dd24cce087eca78353ff231a9c.zip external_llvm-ae285bf5a631e7dd24cce087eca78353ff231a9c.tar.gz external_llvm-ae285bf5a631e7dd24cce087eca78353ff231a9c.tar.bz2 |
Don't try to analyze this "backward" case. This is overly conservative
pending a correct solution.
git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@61589 91177308-0d34-0410-b5e6-96231b3b80d8
Diffstat (limited to 'lib/Analysis')
-rw-r--r-- | lib/Analysis/ScalarEvolution.cpp | 12 |
1 files changed, 12 insertions, 0 deletions
diff --git a/lib/Analysis/ScalarEvolution.cpp b/lib/Analysis/ScalarEvolution.cpp index 142b82d..375ad5e 100644 --- a/lib/Analysis/ScalarEvolution.cpp +++ b/lib/Analysis/ScalarEvolution.cpp @@ -2905,6 +2905,11 @@ bool ScalarEvolutionsImpl::executesAtLeastOnce(const Loop *L, bool isSigned, return false; } +static bool isNegative(SCEVHandle X) { + if (SCEVConstant *C = dyn_cast<SCEVConstant>(X)) + return C->getValue()->getValue().isNegative(); +} + /// potentialInfiniteLoop - Test whether the loop might jump over the exit value /// due to wrapping around 2^n. bool ScalarEvolutionsImpl::potentialInfiniteLoop(SCEV *Stride, SCEV *RHS, @@ -2958,6 +2963,13 @@ HowManyLessThans(SCEV *LHS, SCEV *RHS, const Loop *L, if (potentialInfiniteLoop(Stride, RHS, isSigned, trueWhenEqual)) return UnknownValue; + // We don't handle this correctly at the moment. The problem is that when + // the stride is negative, we're not counting how many times 'less-than' is + // true as we approach it, we're counting how far away we are from wrapping + // around the backside. + if (isSigned && isNegative(Stride)) + return UnknownValue; + // We know the LHS is of the form {n,+,s} and the RHS is some loop-invariant // m. So, we count the number of iterations in which {n,+,s} < m is true. // Note that we cannot simply return max(m-n,0)/s because it's not safe to |