diff options
Diffstat (limited to 'lib')
-rw-r--r-- | lib/Transforms/Scalar/SCCP.cpp | 168 |
1 files changed, 1 insertions, 167 deletions
diff --git a/lib/Transforms/Scalar/SCCP.cpp b/lib/Transforms/Scalar/SCCP.cpp index 196a847..f6762ad 100644 --- a/lib/Transforms/Scalar/SCCP.cpp +++ b/lib/Transforms/Scalar/SCCP.cpp @@ -201,10 +201,6 @@ class SCCPSolver : public InstVisitor<SCCPSolver> { SmallVector<BasicBlock*, 64> BBWorkList; // The BasicBlock work list - /// UsersOfOverdefinedPHIs - Keep track of any users of PHI nodes that are not - /// overdefined, despite the fact that the PHI node is overdefined. - std::multimap<PHINode*, Instruction*> UsersOfOverdefinedPHIs; - /// KnownFeasibleEdges - Entries in this set are edges which have already had /// PHI nodes retriggered. typedef std::pair<BasicBlock*, BasicBlock*> Edge; @@ -466,33 +462,6 @@ private: if (BBExecutable.count(I->getParent())) // Inst is executable? visit(*I); } - - /// RemoveFromOverdefinedPHIs - If I has any entries in the - /// UsersOfOverdefinedPHIs map for PN, remove them now. - void RemoveFromOverdefinedPHIs(Instruction *I, PHINode *PN) { - if (UsersOfOverdefinedPHIs.empty()) return; - typedef std::multimap<PHINode*, Instruction*>::iterator ItTy; - std::pair<ItTy, ItTy> Range = UsersOfOverdefinedPHIs.equal_range(PN); - for (ItTy It = Range.first, E = Range.second; It != E;) { - if (It->second == I) - UsersOfOverdefinedPHIs.erase(It++); - else - ++It; - } - } - - /// InsertInOverdefinedPHIs - Insert an entry in the UsersOfOverdefinedPHIS - /// map for I and PN, but if one is there already, do not create another. - /// (Duplicate entries do not break anything directly, but can lead to - /// exponential growth of the table in rare cases.) - void InsertInOverdefinedPHIs(Instruction *I, PHINode *PN) { - typedef std::multimap<PHINode*, Instruction*>::iterator ItTy; - std::pair<ItTy, ItTy> Range = UsersOfOverdefinedPHIs.equal_range(PN); - for (ItTy J = Range.first, E = Range.second; J != E; ++J) - if (J->second == I) - return; - UsersOfOverdefinedPHIs.insert(std::make_pair(PN, I)); - } private: friend class InstVisitor<SCCPSolver>; @@ -700,23 +669,8 @@ void SCCPSolver::visitPHINode(PHINode &PN) { if (PN.getType()->isStructTy()) return markAnythingOverdefined(&PN); - if (getValueState(&PN).isOverdefined()) { - // There may be instructions using this PHI node that are not overdefined - // themselves. If so, make sure that they know that the PHI node operand - // changed. - typedef std::multimap<PHINode*, Instruction*>::iterator ItTy; - std::pair<ItTy, ItTy> Range = UsersOfOverdefinedPHIs.equal_range(&PN); - - if (Range.first == Range.second) - return; - - SmallVector<Instruction*, 16> Users; - for (ItTy I = Range.first, E = Range.second; I != E; ++I) - Users.push_back(I->second); - while (!Users.empty()) - visit(Users.pop_back_val()); + if (getValueState(&PN).isOverdefined()) return; // Quick exit - } // Super-extra-high-degree PHI nodes are unlikely to ever be marked constant, // and slow us down a lot. Just mark them overdefined. @@ -959,64 +913,6 @@ void SCCPSolver::visitBinaryOperator(Instruction &I) { } - // If both operands are PHI nodes, it is possible that this instruction has - // a constant value, despite the fact that the PHI node doesn't. Check for - // this condition now. - if (PHINode *PN1 = dyn_cast<PHINode>(I.getOperand(0))) - if (PHINode *PN2 = dyn_cast<PHINode>(I.getOperand(1))) - if (PN1->getParent() == PN2->getParent()) { - // Since the two PHI nodes are in the same basic block, they must have - // entries for the same predecessors. Walk the predecessor list, and - // if all of the incoming values are constants, and the result of - // evaluating this expression with all incoming value pairs is the - // same, then this expression is a constant even though the PHI node - // is not a constant! - LatticeVal Result; - for (unsigned i = 0, e = PN1->getNumIncomingValues(); i != e; ++i) { - LatticeVal In1 = getValueState(PN1->getIncomingValue(i)); - BasicBlock *InBlock = PN1->getIncomingBlock(i); - LatticeVal In2 =getValueState(PN2->getIncomingValueForBlock(InBlock)); - - if (In1.isOverdefined() || In2.isOverdefined()) { - Result.markOverdefined(); - break; // Cannot fold this operation over the PHI nodes! - } - - if (In1.isConstant() && In2.isConstant()) { - Constant *V = ConstantExpr::get(I.getOpcode(), In1.getConstant(), - In2.getConstant()); - if (Result.isUndefined()) - Result.markConstant(V); - else if (Result.isConstant() && Result.getConstant() != V) { - Result.markOverdefined(); - break; - } - } - } - - // If we found a constant value here, then we know the instruction is - // constant despite the fact that the PHI nodes are overdefined. - if (Result.isConstant()) { - markConstant(IV, &I, Result.getConstant()); - // Remember that this instruction is virtually using the PHI node - // operands. - InsertInOverdefinedPHIs(&I, PN1); - InsertInOverdefinedPHIs(&I, PN2); - return; - } - - if (Result.isUndefined()) - return; - - // Okay, this really is overdefined now. Since we might have - // speculatively thought that this was not overdefined before, and - // added ourselves to the UsersOfOverdefinedPHIs list for the PHIs, - // make sure to clean out any entries that we put there, for - // efficiency. - RemoveFromOverdefinedPHIs(&I, PN1); - RemoveFromOverdefinedPHIs(&I, PN2); - } - markOverdefined(&I); } @@ -1037,68 +933,6 @@ void SCCPSolver::visitCmpInst(CmpInst &I) { if (!V1State.isOverdefined() && !V2State.isOverdefined()) return; - // If something is overdefined, use some tricks to avoid ending up and over - // defined if we can. - - // If both operands are PHI nodes, it is possible that this instruction has - // a constant value, despite the fact that the PHI node doesn't. Check for - // this condition now. - if (PHINode *PN1 = dyn_cast<PHINode>(I.getOperand(0))) - if (PHINode *PN2 = dyn_cast<PHINode>(I.getOperand(1))) - if (PN1->getParent() == PN2->getParent()) { - // Since the two PHI nodes are in the same basic block, they must have - // entries for the same predecessors. Walk the predecessor list, and - // if all of the incoming values are constants, and the result of - // evaluating this expression with all incoming value pairs is the - // same, then this expression is a constant even though the PHI node - // is not a constant! - LatticeVal Result; - for (unsigned i = 0, e = PN1->getNumIncomingValues(); i != e; ++i) { - LatticeVal In1 = getValueState(PN1->getIncomingValue(i)); - BasicBlock *InBlock = PN1->getIncomingBlock(i); - LatticeVal In2 =getValueState(PN2->getIncomingValueForBlock(InBlock)); - - if (In1.isOverdefined() || In2.isOverdefined()) { - Result.markOverdefined(); - break; // Cannot fold this operation over the PHI nodes! - } - - if (In1.isConstant() && In2.isConstant()) { - Constant *V = ConstantExpr::getCompare(I.getPredicate(), - In1.getConstant(), - In2.getConstant()); - if (Result.isUndefined()) - Result.markConstant(V); - else if (Result.isConstant() && Result.getConstant() != V) { - Result.markOverdefined(); - break; - } - } - } - - // If we found a constant value here, then we know the instruction is - // constant despite the fact that the PHI nodes are overdefined. - if (Result.isConstant()) { - markConstant(&I, Result.getConstant()); - // Remember that this instruction is virtually using the PHI node - // operands. - InsertInOverdefinedPHIs(&I, PN1); - InsertInOverdefinedPHIs(&I, PN2); - return; - } - - if (Result.isUndefined()) - return; - - // Okay, this really is overdefined now. Since we might have - // speculatively thought that this was not overdefined before, and - // added ourselves to the UsersOfOverdefinedPHIs list for the PHIs, - // make sure to clean out any entries that we put there, for - // efficiency. - RemoveFromOverdefinedPHIs(&I, PN1); - RemoveFromOverdefinedPHIs(&I, PN2); - } - markOverdefined(&I); } |