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; This testcase failed due to a bad assertion in SymbolTable.cpp, removed in the 1.20 revision
; Basically the symbol table assumed that if there was an abstract type in the symbol table,
; [in this case for the entry %foo of type void(opaque)* ], that there should have also been
; named types by now. This was obviously not the case here, and this is valid. Assertion
; disabled.
declare void "foo"(%bb)
%bb = type int
implementation
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