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; This test makes sure that add instructions are properly eliminated.
; This test is for Integer BitWidth > 64 && BitWidth <= 1024.
; RUN: llvm-as < %s | opt -instcombine | llvm-dis | \
; RUN: grep -v OK | not grep add
; END.
define i111 @test1(i111 %x) {
%tmp.2 = shl i111 1, 110
%tmp.4 = xor i111 %x, %tmp.2
;; Add of sign bit -> xor of sign bit.
%tmp.6 = add i111 %tmp.4, %tmp.2
ret i111 %tmp.6
}
define i65 @test2(i65 %x) {
%tmp.0 = shl i65 1, 64
%tmp.2 = xor i65 %x, %tmp.0
;; Add of sign bit -> xor of sign bit.
%tmp.4 = add i65 %tmp.2, %tmp.0
ret i65 %tmp.4
}
define i1024 @test3(i1024 %x) {
%tmp.0 = shl i1024 1, 1023
%tmp.2 = xor i1024 %x, %tmp.0
;; Add of sign bit -> xor of sign bit.
%tmp.4 = add i1024 %tmp.2, %tmp.0
ret i1024 %tmp.4
}
define i128 @test4(i128 %x) {
;; If we have ADD(XOR(AND(X, 0xFF), 0xF..F80), 0x80), it's a sext.
%tmp.5 = shl i128 1, 127
%tmp.1 = ashr i128 %tmp.5, 120
%tmp.2 = xor i128 %x, %tmp.1
%tmp.4 = add i128 %tmp.2, %tmp.5
ret i128 %tmp.4
}
define i77 @test6(i77 %x) {
;; (x & 254)+1 -> (x & 254)|1
%tmp.2 = and i77 %x, 562949953421310
%tmp.4 = add i77 %tmp.2, 1
ret i77 %tmp.4
}
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