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Diffstat (limited to 'JavaScriptCore/tests/mozilla/ecma/Expressions/11.5.2.js')
| -rw-r--r-- | JavaScriptCore/tests/mozilla/ecma/Expressions/11.5.2.js | 154 |
1 files changed, 0 insertions, 154 deletions
diff --git a/JavaScriptCore/tests/mozilla/ecma/Expressions/11.5.2.js b/JavaScriptCore/tests/mozilla/ecma/Expressions/11.5.2.js deleted file mode 100644 index c681a35..0000000 --- a/JavaScriptCore/tests/mozilla/ecma/Expressions/11.5.2.js +++ /dev/null @@ -1,154 +0,0 @@ -/* The contents of this file are subject to the Netscape Public - * License Version 1.1 (the "License"); you may not use this file - * except in compliance with the License. You may obtain a copy of - * the License at http://www.mozilla.org/NPL/ - * - * Software distributed under the License is distributed on an "AS - * IS" basis, WITHOUT WARRANTY OF ANY KIND, either express or - * implied. See the License for the specific language governing - * rights and limitations under the License. - * - * The Original Code is Mozilla Communicator client code, released March - * 31, 1998. - * - * The Initial Developer of the Original Code is Netscape Communications - * Corporation. Portions created by Netscape are - * Copyright (C) 1998 Netscape Communications Corporation. All - * Rights Reserved. - * - * Contributor(s): - * - */ -/** - File Name: 11.5.2.js - ECMA Section: 11.5.2 Applying the / operator - Description: - - The / operator performs division, producing the quotient of its operands. - The left operand is the dividend and the right operand is the divisor. - ECMAScript does not perform integer division. The operands and result of all - division operations are double-precision floating-point numbers. - The result of division is determined by the specification of IEEE 754 arithmetic: - - If either operand is NaN, the result is NaN. - The sign of the result is positive if both operands have the same sign, negative if the operands have different - signs. - Division of an infinity by an infinity results in NaN. - Division of an infinity by a zero results in an infinity. The sign is determined by the rule already stated above. - Division of an infinity by a non-zero finite value results in a signed infinity. The sign is determined by the rule - already stated above. - Division of a finite value by an infinity results in zero. The sign is determined by the rule already stated above. - Division of a zero by a zero results in NaN; division of zero by any other finite value results in zero, with the sign - determined by the rule already stated above. - Division of a non-zero finite value by a zero results in a signed infinity. The sign is determined by the rule - already stated above. - In the remaining cases, where neither an infinity, nor a zero, nor NaN is involved, the quotient is computed and - rounded to the nearest representable value using IEEE 754 round-to-nearest mode. If the magnitude is too - large to represent, we say the operation overflows; the result is then an infinity of appropriate sign. If the - magnitude is too small to represent, we say the operation underflows and the result is a zero of the appropriate - sign. The ECMAScript language requires support of gradual underflow as defined by IEEE 754. - - Author: christine@netscape.com - Date: 12 november 1997 -*/ - var SECTION = "11.5.2"; - var VERSION = "ECMA_1"; - startTest(); - var testcases = getTestCases(); - var BUGNUMBER="111202"; - - writeHeaderToLog( SECTION + " Applying the / operator"); - test(); - -function test() { - for ( tc=0; tc < testcases.length; tc++ ) { - testcases[tc].passed = writeTestCaseResult( - testcases[tc].expect, - testcases[tc].actual, - testcases[tc].description +" = "+ - testcases[tc].actual ); - - testcases[tc].reason += ( testcases[tc].passed ) ? "" : "wrong value "; - } - stopTest(); - return ( testcases ); -} -function getTestCases() { - var array = new Array(); - var item = 0; - - // if either operand is NaN, the result is NaN. - - array[item++] = new TestCase( SECTION, "Number.NaN / Number.NaN", Number.NaN, Number.NaN / Number.NaN ); - array[item++] = new TestCase( SECTION, "Number.NaN / 1", Number.NaN, Number.NaN / 1 ); - array[item++] = new TestCase( SECTION, "1 / Number.NaN", Number.NaN, 1 / Number.NaN ); - - array[item++] = new TestCase( SECTION, "Number.POSITIVE_INFINITY / Number.NaN", Number.NaN, Number.POSITIVE_INFINITY / Number.NaN ); - array[item++] = new TestCase( SECTION, "Number.NEGATIVE_INFINITY / Number.NaN", Number.NaN, Number.NEGATIVE_INFINITY / Number.NaN ); - - // Division of an infinity by an infinity results in NaN. - - array[item++] = new TestCase( SECTION, "Number.NEGATIVE_INFINITY / Number.NEGATIVE_INFINITY", Number.NaN, Number.NEGATIVE_INFINITY / Number.NEGATIVE_INFINITY ); - array[item++] = new TestCase( SECTION, "Number.POSITIVE_INFINITY / Number.NEGATIVE_INFINITY", Number.NaN, Number.POSITIVE_INFINITY / Number.NEGATIVE_INFINITY ); - array[item++] = new TestCase( SECTION, "Number.NEGATIVE_INFINITY / Number.POSITIVE_INFINITY", Number.NaN, Number.NEGATIVE_INFINITY / Number.POSITIVE_INFINITY ); - array[item++] = new TestCase( SECTION, "Number.POSITIVE_INFINITY / Number.POSITIVE_INFINITY", Number.NaN, Number.POSITIVE_INFINITY / Number.POSITIVE_INFINITY ); - - // Division of an infinity by a zero results in an infinity. - - array[item++] = new TestCase( SECTION, "Number.POSITIVE_INFINITY / 0", Number.POSITIVE_INFINITY, Number.POSITIVE_INFINITY / 0 ); - array[item++] = new TestCase( SECTION, "Number.NEGATIVE_INFINITY / 0", Number.NEGATIVE_INFINITY, Number.NEGATIVE_INFINITY / 0 ); - array[item++] = new TestCase( SECTION, "Number.POSITIVE_INFINITY / -0", Number.NEGATIVE_INFINITY, Number.POSITIVE_INFINITY / -0 ); - array[item++] = new TestCase( SECTION, "Number.NEGATIVE_INFINITY / -0", Number.POSITIVE_INFINITY, Number.NEGATIVE_INFINITY / -0 ); - - // Division of an infinity by a non-zero finite value results in a signed infinity. - - array[item++] = new TestCase( SECTION, "Number.NEGATIVE_INFINITY / 1 ", Number.NEGATIVE_INFINITY, Number.NEGATIVE_INFINITY / 1 ); - array[item++] = new TestCase( SECTION, "Number.NEGATIVE_INFINITY / -1 ", Number.POSITIVE_INFINITY, Number.NEGATIVE_INFINITY / -1 ); - array[item++] = new TestCase( SECTION, "Number.POSITIVE_INFINITY / 1 ", Number.POSITIVE_INFINITY, Number.POSITIVE_INFINITY / 1 ); - array[item++] = new TestCase( SECTION, "Number.POSITIVE_INFINITY / -1 ", Number.NEGATIVE_INFINITY, Number.POSITIVE_INFINITY / -1 ); - - array[item++] = new TestCase( SECTION, "Number.NEGATIVE_INFINITY / Number.MAX_VALUE ", Number.NEGATIVE_INFINITY, Number.NEGATIVE_INFINITY / Number.MAX_VALUE ); - array[item++] = new TestCase( SECTION, "Number.NEGATIVE_INFINITY / -Number.MAX_VALUE ", Number.POSITIVE_INFINITY, Number.NEGATIVE_INFINITY / -Number.MAX_VALUE ); - array[item++] = new TestCase( SECTION, "Number.POSITIVE_INFINITY / Number.MAX_VALUE ", Number.POSITIVE_INFINITY, Number.POSITIVE_INFINITY / Number.MAX_VALUE ); - array[item++] = new TestCase( SECTION, "Number.POSITIVE_INFINITY / -Number.MAX_VALUE ", Number.NEGATIVE_INFINITY, Number.POSITIVE_INFINITY / -Number.MAX_VALUE ); - - // Division of a finite value by an infinity results in zero. - - array[item++] = new TestCase( SECTION, "1 / Number.NEGATIVE_INFINITY", -0, 1 / Number.NEGATIVE_INFINITY ); - array[item++] = new TestCase( SECTION, "1 / Number.POSITIVE_INFINITY", 0, 1 / Number.POSITIVE_INFINITY ); - array[item++] = new TestCase( SECTION, "-1 / Number.POSITIVE_INFINITY", -0, -1 / Number.POSITIVE_INFINITY ); - array[item++] = new TestCase( SECTION, "-1 / Number.NEGATIVE_INFINITY", 0, -1 / Number.NEGATIVE_INFINITY ); - - array[item++] = new TestCase( SECTION, "Number.MAX_VALUE / Number.NEGATIVE_INFINITY", -0, Number.MAX_VALUE / Number.NEGATIVE_INFINITY ); - array[item++] = new TestCase( SECTION, "Number.MAX_VALUE / Number.POSITIVE_INFINITY", 0, Number.MAX_VALUE / Number.POSITIVE_INFINITY ); - array[item++] = new TestCase( SECTION, "-Number.MAX_VALUE / Number.POSITIVE_INFINITY", -0, -Number.MAX_VALUE / Number.POSITIVE_INFINITY ); - array[item++] = new TestCase( SECTION, "-Number.MAX_VALUE / Number.NEGATIVE_INFINITY", 0, -Number.MAX_VALUE / Number.NEGATIVE_INFINITY ); - - // Division of a zero by a zero results in NaN - - array[item++] = new TestCase( SECTION, "0 / -0", Number.NaN, 0 / -0 ); - array[item++] = new TestCase( SECTION, "-0 / 0", Number.NaN, -0 / 0 ); - array[item++] = new TestCase( SECTION, "-0 / -0", Number.NaN, -0 / -0 ); - array[item++] = new TestCase( SECTION, "0 / 0", Number.NaN, 0 / 0 ); - - // division of zero by any other finite value results in zero - - array[item++] = new TestCase( SECTION, "0 / 1", 0, 0 / 1 ); - array[item++] = new TestCase( SECTION, "0 / -1", -0, 0 / -1 ); - array[item++] = new TestCase( SECTION, "-0 / 1", -0, -0 / 1 ); - array[item++] = new TestCase( SECTION, "-0 / -1", 0, -0 / -1 ); - - // Division of a non-zero finite value by a zero results in a signed infinity. - - array[item++] = new TestCase( SECTION, "1 / 0", Number.POSITIVE_INFINITY, 1/0 ); - array[item++] = new TestCase( SECTION, "1 / -0", Number.NEGATIVE_INFINITY, 1/-0 ); - array[item++] = new TestCase( SECTION, "-1 / 0", Number.NEGATIVE_INFINITY, -1/0 ); - array[item++] = new TestCase( SECTION, "-1 / -0", Number.POSITIVE_INFINITY, -1/-0 ); - - array[item++] = new TestCase( SECTION, "0 / Number.POSITIVE_INFINITY", 0, 0 / Number.POSITIVE_INFINITY ); - array[item++] = new TestCase( SECTION, "0 / Number.NEGATIVE_INFINITY", -0, 0 / Number.NEGATIVE_INFINITY ); - array[item++] = new TestCase( SECTION, "-0 / Number.POSITIVE_INFINITY", -0, -0 / Number.POSITIVE_INFINITY ); - array[item++] = new TestCase( SECTION, "-0 / Number.NEGATIVE_INFINITY", 0, -0 / Number.NEGATIVE_INFINITY ); - - return ( array ); -} |