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Diffstat (limited to 'JavaScriptCore/tests/mozilla/ecma/Math/15.8.2.18.js')
| -rw-r--r-- | JavaScriptCore/tests/mozilla/ecma/Math/15.8.2.18.js | 98 |
1 files changed, 0 insertions, 98 deletions
diff --git a/JavaScriptCore/tests/mozilla/ecma/Math/15.8.2.18.js b/JavaScriptCore/tests/mozilla/ecma/Math/15.8.2.18.js deleted file mode 100644 index f745dd7..0000000 --- a/JavaScriptCore/tests/mozilla/ecma/Math/15.8.2.18.js +++ /dev/null @@ -1,98 +0,0 @@ -/* The contents of this file are subject to the Netscape Public - * License Version 1.1 (the "License"); you may not use this file - * except in compliance with the License. You may obtain a copy of - * the License at http://www.mozilla.org/NPL/ - * - * Software distributed under the License is distributed on an "AS - * IS" basis, WITHOUT WARRANTY OF ANY KIND, either express or - * implied. See the License for the specific language governing - * rights and limitations under the License. - * - * The Original Code is Mozilla Communicator client code, released March - * 31, 1998. - * - * The Initial Developer of the Original Code is Netscape Communications - * Corporation. Portions created by Netscape are - * Copyright (C) 1998 Netscape Communications Corporation. All - * Rights Reserved. - * - * Contributor(s): - * - */ -/** - File Name: 15.8.2.18.js - ECMA Section: 15.8.2.18 tan( x ) - Description: return an approximation to the tan of the - argument. argument is expressed in radians - special cases: - - if x is NaN result is NaN - - if x is 0 result is 0 - - if x is -0 result is -0 - - if x is Infinity or -Infinity result is NaN - Author: christine@netscape.com - Date: 7 july 1997 -*/ - - var SECTION = "15.8.2.18"; - var VERSION = "ECMA_1"; - startTest(); - var TITLE = "Math.tan(x)"; - var EXCLUDE = "true"; - - writeHeaderToLog( SECTION + " "+ TITLE); - - var testcases = getTestCases(); - test(); - -function getTestCases() { - var array = new Array(); - var item = 0; - - array[item++] = new TestCase( SECTION, "Math.tan.length", 1, Math.tan.length ); - - array[item++] = new TestCase( SECTION, "Math.tan()", Number.NaN, Math.tan() ); - array[item++] = new TestCase( SECTION, "Math.tan(void 0)", Number.NaN, Math.tan(void 0)); - array[item++] = new TestCase( SECTION, "Math.tan(null)", 0, Math.tan(null) ); - array[item++] = new TestCase( SECTION, "Math.tan(false)", 0, Math.tan(false) ); - - array[item++] = new TestCase( SECTION, "Math.tan(NaN)", Number.NaN, Math.tan(Number.NaN) ); - array[item++] = new TestCase( SECTION, "Math.tan(0)", 0, Math.tan(0)); - array[item++] = new TestCase( SECTION, "Math.tan(-0)", -0, Math.tan(-0)); - array[item++] = new TestCase( SECTION, "Math.tan(Infinity)", Number.NaN, Math.tan(Number.POSITIVE_INFINITY)); - array[item++] = new TestCase( SECTION, "Math.tan(-Infinity)", Number.NaN, Math.tan(Number.NEGATIVE_INFINITY)); - array[item++] = new TestCase( SECTION, "Math.tan(Math.PI/4)", 1, Math.tan(Math.PI/4)); - array[item++] = new TestCase( SECTION, "Math.tan(3*Math.PI/4)", -1, Math.tan(3*Math.PI/4)); - array[item++] = new TestCase( SECTION, "Math.tan(Math.PI)", -0, Math.tan(Math.PI)); - array[item++] = new TestCase( SECTION, "Math.tan(5*Math.PI/4)", 1, Math.tan(5*Math.PI/4)); - array[item++] = new TestCase( SECTION, "Math.tan(7*Math.PI/4)", -1, Math.tan(7*Math.PI/4)); - array[item++] = new TestCase( SECTION, "Infinity/Math.tan(-0)", -Infinity, Infinity/Math.tan(-0) ); - -/* - Arctan (x) ~ PI/2 - 1/x for large x. For x = 1.6x10^16, 1/x is about the last binary digit of double precision PI/2. - That is to say, perturbing PI/2 by this much is about the smallest rounding error possible. - - This suggests that the answer Christine is getting and a real Infinity are "adjacent" results from the tangent function. I - suspect that tan (PI/2 + one ulp) is a negative result about the same size as tan (PI/2) and that this pair are the closest - results to infinity that the algorithm can deliver. - - In any case, my call is that the answer we're seeing is "right". I suggest the test pass on any result this size or larger. - = C = -*/ - array[item++] = new TestCase( SECTION, "Math.tan(3*Math.PI/2) >= 5443000000000000", true, Math.tan(3*Math.PI/2) >= 5443000000000000 ); - array[item++] = new TestCase( SECTION, "Math.tan(Math.PI/2) >= 5443000000000000", true, Math.tan(Math.PI/2) >= 5443000000000000 ); - - return ( array ); -} -function test() { - for ( tc=0; tc < testcases.length; tc++ ) { - testcases[tc].passed = writeTestCaseResult( - testcases[tc].expect, - testcases[tc].actual, - testcases[tc].description +" = "+ - testcases[tc].actual ); - - testcases[tc].reason += ( testcases[tc].passed ) ? "" : "wrong value "; - } - stopTest(); - return ( testcases ); -} |