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Diffstat (limited to 'Source/JavaScriptCore/tests/mozilla/ecma/Expressions/11.5.2.js')
| -rw-r--r-- | Source/JavaScriptCore/tests/mozilla/ecma/Expressions/11.5.2.js | 154 |
1 files changed, 154 insertions, 0 deletions
diff --git a/Source/JavaScriptCore/tests/mozilla/ecma/Expressions/11.5.2.js b/Source/JavaScriptCore/tests/mozilla/ecma/Expressions/11.5.2.js new file mode 100644 index 0000000..c681a35 --- /dev/null +++ b/Source/JavaScriptCore/tests/mozilla/ecma/Expressions/11.5.2.js @@ -0,0 +1,154 @@ +/* The contents of this file are subject to the Netscape Public + * License Version 1.1 (the "License"); you may not use this file + * except in compliance with the License. You may obtain a copy of + * the License at http://www.mozilla.org/NPL/ + * + * Software distributed under the License is distributed on an "AS + * IS" basis, WITHOUT WARRANTY OF ANY KIND, either express or + * implied. See the License for the specific language governing + * rights and limitations under the License. + * + * The Original Code is Mozilla Communicator client code, released March + * 31, 1998. + * + * The Initial Developer of the Original Code is Netscape Communications + * Corporation. Portions created by Netscape are + * Copyright (C) 1998 Netscape Communications Corporation. All + * Rights Reserved. + * + * Contributor(s): + * + */ +/** + File Name: 11.5.2.js + ECMA Section: 11.5.2 Applying the / operator + Description: + + The / operator performs division, producing the quotient of its operands. + The left operand is the dividend and the right operand is the divisor. + ECMAScript does not perform integer division. The operands and result of all + division operations are double-precision floating-point numbers. + The result of division is determined by the specification of IEEE 754 arithmetic: + + If either operand is NaN, the result is NaN. + The sign of the result is positive if both operands have the same sign, negative if the operands have different + signs. + Division of an infinity by an infinity results in NaN. + Division of an infinity by a zero results in an infinity. The sign is determined by the rule already stated above. + Division of an infinity by a non-zero finite value results in a signed infinity. The sign is determined by the rule + already stated above. + Division of a finite value by an infinity results in zero. The sign is determined by the rule already stated above. + Division of a zero by a zero results in NaN; division of zero by any other finite value results in zero, with the sign + determined by the rule already stated above. + Division of a non-zero finite value by a zero results in a signed infinity. The sign is determined by the rule + already stated above. + In the remaining cases, where neither an infinity, nor a zero, nor NaN is involved, the quotient is computed and + rounded to the nearest representable value using IEEE 754 round-to-nearest mode. If the magnitude is too + large to represent, we say the operation overflows; the result is then an infinity of appropriate sign. If the + magnitude is too small to represent, we say the operation underflows and the result is a zero of the appropriate + sign. The ECMAScript language requires support of gradual underflow as defined by IEEE 754. + + Author: christine@netscape.com + Date: 12 november 1997 +*/ + var SECTION = "11.5.2"; + var VERSION = "ECMA_1"; + startTest(); + var testcases = getTestCases(); + var BUGNUMBER="111202"; + + writeHeaderToLog( SECTION + " Applying the / operator"); + test(); + +function test() { + for ( tc=0; tc < testcases.length; tc++ ) { + testcases[tc].passed = writeTestCaseResult( + testcases[tc].expect, + testcases[tc].actual, + testcases[tc].description +" = "+ + testcases[tc].actual ); + + testcases[tc].reason += ( testcases[tc].passed ) ? "" : "wrong value "; + } + stopTest(); + return ( testcases ); +} +function getTestCases() { + var array = new Array(); + var item = 0; + + // if either operand is NaN, the result is NaN. + + array[item++] = new TestCase( SECTION, "Number.NaN / Number.NaN", Number.NaN, Number.NaN / Number.NaN ); + array[item++] = new TestCase( SECTION, "Number.NaN / 1", Number.NaN, Number.NaN / 1 ); + array[item++] = new TestCase( SECTION, "1 / Number.NaN", Number.NaN, 1 / Number.NaN ); + + array[item++] = new TestCase( SECTION, "Number.POSITIVE_INFINITY / Number.NaN", Number.NaN, Number.POSITIVE_INFINITY / Number.NaN ); + array[item++] = new TestCase( SECTION, "Number.NEGATIVE_INFINITY / Number.NaN", Number.NaN, Number.NEGATIVE_INFINITY / Number.NaN ); + + // Division of an infinity by an infinity results in NaN. + + array[item++] = new TestCase( SECTION, "Number.NEGATIVE_INFINITY / Number.NEGATIVE_INFINITY", Number.NaN, Number.NEGATIVE_INFINITY / Number.NEGATIVE_INFINITY ); + array[item++] = new TestCase( SECTION, "Number.POSITIVE_INFINITY / Number.NEGATIVE_INFINITY", Number.NaN, Number.POSITIVE_INFINITY / Number.NEGATIVE_INFINITY ); + array[item++] = new TestCase( SECTION, "Number.NEGATIVE_INFINITY / Number.POSITIVE_INFINITY", Number.NaN, Number.NEGATIVE_INFINITY / Number.POSITIVE_INFINITY ); + array[item++] = new TestCase( SECTION, "Number.POSITIVE_INFINITY / Number.POSITIVE_INFINITY", Number.NaN, Number.POSITIVE_INFINITY / Number.POSITIVE_INFINITY ); + + // Division of an infinity by a zero results in an infinity. + + array[item++] = new TestCase( SECTION, "Number.POSITIVE_INFINITY / 0", Number.POSITIVE_INFINITY, Number.POSITIVE_INFINITY / 0 ); + array[item++] = new TestCase( SECTION, "Number.NEGATIVE_INFINITY / 0", Number.NEGATIVE_INFINITY, Number.NEGATIVE_INFINITY / 0 ); + array[item++] = new TestCase( SECTION, "Number.POSITIVE_INFINITY / -0", Number.NEGATIVE_INFINITY, Number.POSITIVE_INFINITY / -0 ); + array[item++] = new TestCase( SECTION, "Number.NEGATIVE_INFINITY / -0", Number.POSITIVE_INFINITY, Number.NEGATIVE_INFINITY / -0 ); + + // Division of an infinity by a non-zero finite value results in a signed infinity. + + array[item++] = new TestCase( SECTION, "Number.NEGATIVE_INFINITY / 1 ", Number.NEGATIVE_INFINITY, Number.NEGATIVE_INFINITY / 1 ); + array[item++] = new TestCase( SECTION, "Number.NEGATIVE_INFINITY / -1 ", Number.POSITIVE_INFINITY, Number.NEGATIVE_INFINITY / -1 ); + array[item++] = new TestCase( SECTION, "Number.POSITIVE_INFINITY / 1 ", Number.POSITIVE_INFINITY, Number.POSITIVE_INFINITY / 1 ); + array[item++] = new TestCase( SECTION, "Number.POSITIVE_INFINITY / -1 ", Number.NEGATIVE_INFINITY, Number.POSITIVE_INFINITY / -1 ); + + array[item++] = new TestCase( SECTION, "Number.NEGATIVE_INFINITY / Number.MAX_VALUE ", Number.NEGATIVE_INFINITY, Number.NEGATIVE_INFINITY / Number.MAX_VALUE ); + array[item++] = new TestCase( SECTION, "Number.NEGATIVE_INFINITY / -Number.MAX_VALUE ", Number.POSITIVE_INFINITY, Number.NEGATIVE_INFINITY / -Number.MAX_VALUE ); + array[item++] = new TestCase( SECTION, "Number.POSITIVE_INFINITY / Number.MAX_VALUE ", Number.POSITIVE_INFINITY, Number.POSITIVE_INFINITY / Number.MAX_VALUE ); + array[item++] = new TestCase( SECTION, "Number.POSITIVE_INFINITY / -Number.MAX_VALUE ", Number.NEGATIVE_INFINITY, Number.POSITIVE_INFINITY / -Number.MAX_VALUE ); + + // Division of a finite value by an infinity results in zero. + + array[item++] = new TestCase( SECTION, "1 / Number.NEGATIVE_INFINITY", -0, 1 / Number.NEGATIVE_INFINITY ); + array[item++] = new TestCase( SECTION, "1 / Number.POSITIVE_INFINITY", 0, 1 / Number.POSITIVE_INFINITY ); + array[item++] = new TestCase( SECTION, "-1 / Number.POSITIVE_INFINITY", -0, -1 / Number.POSITIVE_INFINITY ); + array[item++] = new TestCase( SECTION, "-1 / Number.NEGATIVE_INFINITY", 0, -1 / Number.NEGATIVE_INFINITY ); + + array[item++] = new TestCase( SECTION, "Number.MAX_VALUE / Number.NEGATIVE_INFINITY", -0, Number.MAX_VALUE / Number.NEGATIVE_INFINITY ); + array[item++] = new TestCase( SECTION, "Number.MAX_VALUE / Number.POSITIVE_INFINITY", 0, Number.MAX_VALUE / Number.POSITIVE_INFINITY ); + array[item++] = new TestCase( SECTION, "-Number.MAX_VALUE / Number.POSITIVE_INFINITY", -0, -Number.MAX_VALUE / Number.POSITIVE_INFINITY ); + array[item++] = new TestCase( SECTION, "-Number.MAX_VALUE / Number.NEGATIVE_INFINITY", 0, -Number.MAX_VALUE / Number.NEGATIVE_INFINITY ); + + // Division of a zero by a zero results in NaN + + array[item++] = new TestCase( SECTION, "0 / -0", Number.NaN, 0 / -0 ); + array[item++] = new TestCase( SECTION, "-0 / 0", Number.NaN, -0 / 0 ); + array[item++] = new TestCase( SECTION, "-0 / -0", Number.NaN, -0 / -0 ); + array[item++] = new TestCase( SECTION, "0 / 0", Number.NaN, 0 / 0 ); + + // division of zero by any other finite value results in zero + + array[item++] = new TestCase( SECTION, "0 / 1", 0, 0 / 1 ); + array[item++] = new TestCase( SECTION, "0 / -1", -0, 0 / -1 ); + array[item++] = new TestCase( SECTION, "-0 / 1", -0, -0 / 1 ); + array[item++] = new TestCase( SECTION, "-0 / -1", 0, -0 / -1 ); + + // Division of a non-zero finite value by a zero results in a signed infinity. + + array[item++] = new TestCase( SECTION, "1 / 0", Number.POSITIVE_INFINITY, 1/0 ); + array[item++] = new TestCase( SECTION, "1 / -0", Number.NEGATIVE_INFINITY, 1/-0 ); + array[item++] = new TestCase( SECTION, "-1 / 0", Number.NEGATIVE_INFINITY, -1/0 ); + array[item++] = new TestCase( SECTION, "-1 / -0", Number.POSITIVE_INFINITY, -1/-0 ); + + array[item++] = new TestCase( SECTION, "0 / Number.POSITIVE_INFINITY", 0, 0 / Number.POSITIVE_INFINITY ); + array[item++] = new TestCase( SECTION, "0 / Number.NEGATIVE_INFINITY", -0, 0 / Number.NEGATIVE_INFINITY ); + array[item++] = new TestCase( SECTION, "-0 / Number.POSITIVE_INFINITY", -0, -0 / Number.POSITIVE_INFINITY ); + array[item++] = new TestCase( SECTION, "-0 / Number.NEGATIVE_INFINITY", 0, -0 / Number.NEGATIVE_INFINITY ); + + return ( array ); +} |