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| author | Adrian Hunter <ext-adrian.hunter@nokia.com> | 2008-07-30 12:18:02 +0300 |
|---|---|---|
| committer | Artem Bityutskiy <Artem.Bityutskiy@nokia.com> | 2008-08-13 11:39:20 +0300 |
| commit | 3a13252c6f3a029ac992a36910e945f361482797 (patch) | |
| tree | c9d62f776c9761bd15d9b1b5c05f032895c7e8a9 /fs | |
| parent | 22bc7fa8c5da09805edc6a6199ce81373b2c207d (diff) | |
| download | kernel_samsung_aries-3a13252c6f3a029ac992a36910e945f361482797.zip kernel_samsung_aries-3a13252c6f3a029ac992a36910e945f361482797.tar.gz kernel_samsung_aries-3a13252c6f3a029ac992a36910e945f361482797.tar.bz2 | |
UBIFS: correct spelling of "thrice".
Signed-off-by: Adrian Hunter <ext-adrian.hunter@nokia.com>
Diffstat (limited to 'fs')
| -rw-r--r-- | fs/ubifs/budget.c | 4 | ||||
| -rw-r--r-- | fs/ubifs/find.c | 2 |
2 files changed, 3 insertions, 3 deletions
diff --git a/fs/ubifs/budget.c b/fs/ubifs/budget.c index 323d83a..15409815 100644 --- a/fs/ubifs/budget.c +++ b/fs/ubifs/budget.c @@ -263,7 +263,7 @@ int ubifs_calc_min_idx_lebs(struct ubifs_info *c) idx_size = c->old_idx_sz + c->budg_idx_growth + c->budg_uncommitted_idx; - /* And make sure we have trice the index size of space reserved */ + /* And make sure we have thrice the index size of space reserved */ idx_size = idx_size + (idx_size << 1); /* @@ -388,7 +388,7 @@ static int can_use_rp(struct ubifs_info *c) * This function makes sure UBIFS has enough free eraseblocks for index growth * and data. * - * When budgeting index space, UBIFS reserves trice as more LEBs as the index + * When budgeting index space, UBIFS reserves thrice as many LEBs as the index * would take if it was consolidated and written to the flash. This guarantees * that the "in-the-gaps" commit method always succeeds and UBIFS will always * be able to commit dirty index. So this function basically adds amount of diff --git a/fs/ubifs/find.c b/fs/ubifs/find.c index c70c767..adee7b5 100644 --- a/fs/ubifs/find.c +++ b/fs/ubifs/find.c @@ -290,7 +290,7 @@ int ubifs_find_dirty_leb(struct ubifs_info *c, struct ubifs_lprops *ret_lp, idx_lp = idx_heap->arr[0]; sum = idx_lp->free + idx_lp->dirty; /* - * Since we reserve trice as more space for the index than it + * Since we reserve thrice as much space for the index than it * actually takes, it does not make sense to pick indexing LEBs * with less than, say, half LEB of dirty space. May be half is * not the optimal boundary - this should be tested and |