Fix a bug with multiple word insertion.

Bug: 7903831
Change-Id: I5202bc529a570292dd78d8503d8e2cc93b43d354

1 files changed, 14 insertions, 0 deletions

diff --git a/src/com/android/settings/inputmethod/UserDictionaryAddWordContents.java b/src/com/android/settings/inputmethod/UserDictionaryAddWordContents.java
index 4aa73ca..d81703e 100644
--- a/src/com/android/settings/inputmethod/UserDictionaryAddWordContents.java
+++ b/src/com/android/settings/inputmethod/UserDictionaryAddWordContents.java
@@ -57,6 +57,8 @@ public class UserDictionaryAddWordContents {
     private String mLocale;
     private final String mOldWord;
     private final String mOldShortcut;
+    private String mSavedWord;
+    private String mSavedShortcut;
 
     /* package */ UserDictionaryAddWordContents(final View view, final Bundle args) {
         mWordEditText = (EditText)view.findViewById(R.id.user_dictionary_add_word_text);
@@ -78,6 +80,16 @@ public class UserDictionaryAddWordContents {
         updateLocale(args.getString(EXTRA_LOCALE));
     }
 
+    /* package */ UserDictionaryAddWordContents(final View view,
+            final UserDictionaryAddWordContents oldInstanceToBeEdited) {
+        mWordEditText = (EditText)view.findViewById(R.id.user_dictionary_add_word_text);
+        mShortcutEditText = (EditText)view.findViewById(R.id.user_dictionary_add_shortcut);
+        mMode = MODE_EDIT;
+        mOldWord = oldInstanceToBeEdited.mSavedWord;
+        mOldShortcut = oldInstanceToBeEdited.mSavedShortcut;
+        updateLocale(mLocale);
+    }
+
     // locale may be null, this means default locale
     // It may also be the empty string, which means "all locales"
     /* package */ void updateLocale(final String locale) {
@@ -128,6 +140,8 @@ public class UserDictionaryAddWordContents {
             // If the word is somehow empty, don't insert it.
             return UserDictionaryAddWordActivity.CODE_CANCEL;
         }
+        mSavedWord = newWord;
+        mSavedShortcut = newShortcut;
         // If there is no shortcut, and the word already exists in the database, then we
         // should not insert, because either A. the word exists with no shortcut, in which
         // case the exact same thing we want to insert is already there, or B. the word